How to use the Relay Output Module of Industrial Shields

Introduction

This post guides you in how to use the Relay Output Module.

Requirements

Relay Output Module, Take a look at the link to check the module out         Relay Output Module

Description

This module is designed to use 12Vdc digital output to activate relays. The module consists of 10 relays and 10 inputs interconnected between them. When the input I0.X detects a HIGH value, the corresponding relay output RX will close the circuit, X being any value between 0 and 9. This process is completely implemented by hardware. There is no software that interacts with this Relay Outputs Module.

General Features

*The output current is divided into all 10 relays. If all 10 relays are working at the same time, the output current per relay will be 0,08A.

Schematic

When looking at the schematic, there are some things that must be taken into consideration.

Distribution

Implementation

As an example of using, we will use the inputs I0.8-I0.9/and the outputs R0.8-R0.9. This example can be used in any of the other inputs/outputs with the same idea as the examples that we will show in this post.

This is a representation of the functioning of this Output relays module. The module is composed by 2 parts: The input zone and the output zone.

The first thing to take into consideration is the output zone. Although the image only shows R0.9 & R0.8 this can be taken into consideration for any relay output. The voltage that will provide the relays can be chosen in the VCOM(+) and COM(-) pins. In these pins is where it must be placed a DC voltage between 5 and 24V or an AC voltage of 220Vac. The output voltage will be the same for all the relays. 

In order to get an output voltage through the relay, it is required that the associated input reads a HIGH value. The input voltage required to read a HIGH value is 12Vdc. When there are 12V in the I0.9, the internal circuit switches the relay state, enabling the flow of current from VCOM to the R0.9 output. Only if the I0.9 is reading a value, the output will be enabled. 

Examples

- COMMON (VCOM(+)/COM(-)) SUPPLY WITH DIFFERENT VOLTAGES BEHAVIOUR.

As you can see in these two representations, the voltage established on the COMMON supply will be the one that will take the R0.9 & R0.8 outputs. The relays will always provide the supply of the COMMON pins.

- What happens if not connecting an input, although the COMMON is getting supplied. 

Now we are seeing that in I0.8 the value detected is 0V. 

The DC supply on the input I0.8 is not present. This means that the input I0.8 is detecting a LOW value. However I0.9 is getting supplied as in all the examples, so it is getting a HIGH value. We can see now that although the VCOM(+) is getting supplied, the only output that is giving a voltage is the R0.9 as the input is detecting a HIGH value. R0.8 will supply a LOW value (it is important to consider that when the outputs are in the air, they are not established as pull-up or pull-down so its value is unknown).